Calculate the heat absorbed by the system in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a cyclic process,the change in internal energy $\Delta U = 0$. According to the first law of thermodynamics,$\Delta Q = \Delta U + W$. Since $

Vedclass · Accepted Answer

$31.4 	ext{ J}$

Vedclass · Answer

(A) For a cyclic process,the change in internal energy $\Delta U = 0$. According to the first law of thermodynamics,$\Delta Q = \Delta U + W$. Since $\Delta U = 0$,the heat absorbed $\Delta Q$ is equal to the work done $W$ by the system.The work done $W$ in a $P-V$ diagram is equal to the area enclosed by the cycle.The area of an ellipse is given by $A = \pi 	imes a 	imes b$,where $a$ and $b$ are the semi-major and semi-minor axes.From the graph,the pressure range is $100 	ext{ kPa}$ to $300 	ext{ kPa}$,so the semi-axis $a = \frac{300 - 100}{2} = 100 	ext{ kPa} = 10^5 	ext{ Pa}$.The volume range is $200 	ext{ cc}$ to $400 	ext{ cc}$,so the semi-axis $b = \frac{400 - 200}{2} = 100 	ext{ cc} = 100 	imes 10^{-6} 	ext{ m}^3 = 10^{-4} 	ext{ m}^3$.Therefore,$W = \pi 	imes (10^5 	ext{ Pa}) 	imes (10^{-4} 	ext{ m}^3) = 10 \pi 	ext{ J}$.Using $\pi \approx 3.14$,$W = 10 	imes 3.14 = 31.4 	ext{ J}$.Thus,the heat absorbed is $31.4 	ext{ J}$.

Calculate the heat absorbed by the system in going through the process shown in the figure.

Similar Questions

$A$ thermodynamic system is taken from an original state $A$ to an intermediate state $B$ by a linear process as shown in the figure. Its volume is then reduced to the original value from $B$ to $C$ by an isobaric process. The total work done by the gas from $A$ to $B$ and $B$ to $C$ is: (in $J$)

For one complete cycle of a thermodynamic process on a gas as shown in the $P-V$ diagram,which of the following is true?

The given diagram shows four processes,i.e.,isochoric,isobaric,isothermal,and adiabatic. The correct assignment of the processes,in the same order,is given by

The net work done by an ideal gas going through the cycle as shown in the $P-V$ diagram below is

An ideal gas is taken from point $A$ to point $C$ on a $P-V$ diagram through two processes $AOC$ and $ABC$ as shown in the figure. Process $AOC$ is isothermal.

Vedclass Test Series

Exam Paper Generator

Online Exam Module