The molar conductivities of $HCl$,$NaCl$,$CH_{3}COOH$,and $CH_{3}COONa$ at infinite dilution follow the order:

The conductivity of $0.02 \ M$ $KCl$ solution is $0.00250 \ \Omega^{-1} \ cm^{-1}$. What is its molar conductivity?

What happens when the solution of an electrolyte is diluted?

Which of the following $M$ solutions of $KCl$ has the lowest value of specific conductivity?

The conductivity of a centimolar solution of $KCl$ at $25^{\circ} C$ is $0.0210 \, \Omega^{-1} cm^{-1}$ and the resistance of the cell containing the solution at $25^{\circ} C$ is $60 \, \Omega$. The value of the cell constant is $......... \, cm^{-1}$.

Given the following molar conductivities at $25\,\text{}^{\circ}C$: $HCl = 426\,\Omega^{-1}\,cm^{2}\,mol^{-1}$,$NaCl = 126\,\Omega^{-1}\,cm^{2}\,mol^{-1}$,and sodium crotonate $(NaC)$ = $83\,\Omega^{-1}\,cm^{2}\,mol^{-1}$. Calculate the ionization constant $(K_{a})$ of crotonic acid $(HC)$ if the conductivity of a $0.001\,M$ crotonic acid solution is $3.83 \times 10^{-5}\,\Omega^{-1}\,cm^{-1}$.