Calculate the de-Broglie wavelength of an ele | vedclass

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(B) The speed of light $c = 3.00 	imes 10^8 \ m \ s^{-1}$.One percent of the speed of light is $v = (\frac{1}{100}) 	imes (3.00 	imes 10^8 \ m \ s^

Vedclass · Accepted Answer

$2.42 	imes 10^{-10} \ m$

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(B) The speed of light $c = 3.00 	imes 10^8 \ m \ s^{-1}$.One percent of the speed of light is $v = (\frac{1}{100}) 	imes (3.00 	imes 10^8 \ m \ s^{-1}) = 3.00 	imes 10^6 \ m \ s^{-1}$.Momentum of the electron $(p) = m 	imes v$.$p = (9.11 	imes 10^{-31} \ kg) 	imes (3.00 	imes 10^6 \ m \ s^{-1}) = 2.733 	imes 10^{-24} \ kg \ m \ s^{-1}$.The de-Broglie wavelength $(\lambda)$ is given by $\lambda = \frac{h}{p}$.$\lambda = \frac{6.626 	imes 10^{-34} \ J \ s}{2.733 	imes 10^{-24} \ kg \ m \ s^{-1}} = 2.424 	imes 10^{-10} \ m$.

Calculate the de-Broglie wavelength of an electron travelling at $1\%$ of the speed of light.

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