What is the mass of a particle with a wavelen | vedclass

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(C) According to the de-Broglie relation: $\lambda = \frac{h}{mv}$.Here,$h$ is Planck's constant $(6.626 	imes 10^{-34} \ J \ s)$,$v$ is the speed of

Vedclass · Accepted Answer

$1.0 	imes 10^{-32} \ kg$

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(C) According to the de-Broglie relation: $\lambda = \frac{h}{mv}$.Here,$h$ is Planck's constant $(6.626 	imes 10^{-34} \ J \ s)$,$v$ is the speed of the particle,$m$ is the mass,and $\lambda$ is the wavelength.Rearranging the formula to solve for mass: $m = \frac{h}{\lambda 	imes v}$.Given values:$v = 2.0 	imes 10^8 \ m \ s^{-1}$$\lambda = 3.313 \mathring{A} = 3.313 	imes 10^{-10} \ m$Substituting these values into the equation:$m = \frac{6.626 	imes 10^{-34} \ J \ s}{(3.313 	imes 10^{-10} \ m) 	imes (2.0 	imes 10^8 \ m \ s^{-1})}$$m = \frac{6.626 	imes 10^{-34}}{6.626 	imes 10^{-2}} \ kg = 1.0 	imes 10^{-32} \ kg$.Therefore,option $(C)$ is correct.

What is the mass of a particle with a wavelength of $3.313 \mathring{A}$ moving with a speed of $2.0 \times 10^8 \ m \ s^{-1}$?

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