The boiling point of chloroform was raised by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: $\Delta T_b = 0.323 \ K$,$w = 0.5143 \ g$ (mass of solute),$W = 35 \ g$ (mass of solvent),${K_b} = 3.9 \ K \ kg \ mol^{-1}$.Using the formu

Vedclass · Accepted Answer

$177.42$

Vedclass · Answer

(C) Given: $\Delta T_b = 0.323 \ K$,$w = 0.5143 \ g$ (mass of solute),$W = 35 \ g$ (mass of solvent),${K_b} = 3.9 \ K \ kg \ mol^{-1}$.Using the formula for elevation in boiling point: $\Delta T_b = \frac{{K_b 	imes w 	imes 1000}}{{M_2 	imes W}}$.Rearranging for molecular mass $(M_2)$: $M_2 = \frac{{K_b 	imes w 	imes 1000}}{{W 	imes \Delta T_b}}$.Substituting the values: $M_2 = \frac{{3.9 	imes 0.5143 	imes 1000}}{{35 	imes 0.323}}$.$M_2 = \frac{{2005.77}}{{11.305}} = 177.42 \ g/mol$.

The boiling point of chloroform was raised by $0.323 \ K$ when $0.5143 \ g$ of anthracene was dissolved in $35 \ g$ of chloroform. The molecular mass of anthracene is ....... $g/mol$. (${K_b}$ for $CHCl_3 = 3.9 \ K \ kg \ mol^{-1}$)

Similar Questions

The elevation in boiling point of a solution containing $1.8 \ g$ of glucose in $100 \ g$ of solvent is $0.1 \ ^\circ C$. Find the molal elevation constant of the liquid.

Calculate the amount of water evaporated if $2.8 \ kg$ of $2 \ m$ $CaBr_2$ solution is heated to $110 \ ^oC$ at $1 \ atm$ .......... $gm$.
(Given: $K_b$ of water $= 0.5 \ K \ kg/mol$; Atomic mass of $Ca = 40$,$Br = 80$)

The molal elevation constant is the ratio of the elevation of boiling point to the........

$A$ solution containing $12.5 \ g$ of non-electrolyte substance in $250 \ g$ of water shows boiling point elevation of $0.52 \ K$. Calculate the molar mass of the substance. $(K_b = 0.52 \ K \ kg \ mol^{-1})$ ......... $g \ mol^{-1}$.

When salt is dissolved in water,then.....

Vedclass Test Series

Exam Paper Generator

Online Exam Module