$A$ solution containing $12.5 \ g$ of non-electrolyte substance in $250 \ g$ of water shows boiling point elevation of $0.52 \ K$. Calculate the molar mass of the substance. $(K_b = 0.52 \ K \ kg \ mol^{-1})$ ......... $g \ mol^{-1}$.

  • A
    $43.06$
  • B
    $25.3$
  • C
    $16.08$
  • D
    $50$

Explore More

Similar Questions

Which of the following statements is correct for the boiling point of a solvent containing a dissolved solid substance?

$5 \ g$ of a non-volatile organic substance with molar mass $M_A$ is dissolved in $200 \ g$ of tetrahydrofuran. If $K_b$ is the molal elevation constant of tetrahydrofuran,then $\Delta T_b$ will be:

Calculate the molar mass of a non-volatile solute when $5 \ g$ of it is dissolved in $50 \ g$ of solvent,which boils at $119.6^{\circ} C$. $[K_{b} = 3.2 \ K \ kg \ mol^{-1}$,boiling point of pure solvent $= 118^{\circ} C]$.

The elevation in boiling point for a $0.1 \ m$ solution of a solute in $500 \ g$ of benzene is $0.51 \ K$. If $1000 \ g$ of a $0.1 \ m$ solution of the same solute in benzene is added to the above solution,the $\Delta T_b$ for the resulting solution will be ............... $K$.

The molal elevation constant is the ratio of the elevation of boiling point to the........

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo