Average velocity of a particle executing SHM | vedclass

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(D) In one complete vibration,the particle starts from a position,moves to the extreme,returns to the starting position,moves to the other extreme,and

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) In one complete vibration,the particle starts from a position,moves to the extreme,returns to the starting position,moves to the other extreme,and finally returns to the starting position.Therefore,the net displacement of the particle in one complete oscillation is $0$.Since average velocity is defined as the ratio of total displacement to the total time taken,we have:$	ext{Average velocity} = \frac{	ext{Total Displacement}}{	ext{Total Time}} = \frac{0}{T} = 0$.

Average velocity of a particle executing $SHM$ in one complete vibration is

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