Atomic number of anticathode material in an $X$-ray tube is $41$. Wavelength of $K_\alpha$ $X$-ray produced in the tube is ........ $\mathring A$.

The wavelength of the ${K_{\alpha}}$ line for an element of atomic number $43$ is $\lambda$. Then the wavelength of the ${K_{\alpha}}$ line for an element of atomic number $29$ is:

In an $X-ray$ tube,when the accelerating voltage $V$ is halved,the difference between the wavelength of the $K_{\alpha}$ line and the minimum wavelength of the continuous $X-ray$ spectrum:

The shortest wavelength of $X-$rays emitted from an $X-$ray tube depends upon

Electrons of mass $m$ with de-Broglie wavelength $\lambda$ fall on a target. The cut-off wavelength $\lambda_0$ is equal to [$h=$ Planck's constant,$c=$ velocity of light].

When the accelerating voltage applied to the electrons is increased beyond a critical value in an $X$-ray tube,what happens to the $X$-ray spectrum?