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(B) The shortest wavelength (also known as the cut-off wavelength,$\lambda_{min}$) of $X-$rays emitted from an $X-$ray tube is given by the Duane-Hunt

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Voltage applied to tube

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(B) The shortest wavelength (also known as the cut-off wavelength,$\lambda_{min}$) of $X-$rays emitted from an $X-$ray tube is given by the Duane-Hunt law: $\lambda_{min} = \frac{hc}{eV}$.Here,$h$ is Planck's constant,$c$ is the speed of light,$e$ is the charge of an electron,and $V$ is the accelerating potential difference (voltage) applied across the tube.Since $h$,$c$,and $e$ are constants,$\lambda_{min}$ depends inversely on the voltage $V$ applied to the tube.Therefore,the shortest wavelength depends only on the voltage applied to the tube.

The shortest wavelength of $X-$rays emitted from an $X-$ray tube depends upon

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