At constant pressure,what should be the perce | vedclass

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(D) According to Charles's Law,at constant pressure,$V \propto T$.Therefore,$\frac{V_2}{V_1} = \frac{T_2}{T_1}$.Given that the volume increases by $10

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$10$

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(D) According to Charles's Law,at constant pressure,$V \propto T$.Therefore,$\frac{V_2}{V_1} = \frac{T_2}{T_1}$.Given that the volume increases by $10 \%$,$V_2 = 1.10 V_1$.Substituting this into the equation: $\frac{T_2}{T_1} = \frac{1.10 V_1}{V_1} = 1.10$.The percentage increase in temperature is given by $\frac{T_2 - T_1}{T_1} 	imes 100 = (\frac{T_2}{T_1} - 1) 	imes 100$.$= (1.10 - 1) 	imes 100 = 0.10 	imes 100 = 10 \%$.

At constant pressure,what should be the percentage increase in temperature if the volume is increased by $10 \%$?

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