At $T \ K$,the following equation is obtained for a first order reaction: $\log \frac{k}{A} = -\frac{x}{T}$. The activation energy for this reaction is equal to $(R = \text{gas constant})$

  • A
    $2.303 x R$
  • B
    $\frac{2.303 R}{x}$
  • C
    $\frac{x}{2.303 R}$
  • D
    $\frac{1}{2.303 x R}$

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