At 298 K,the value of -frac{Delta[Br^-]}{Del | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the given reaction: $5 Br^- (aq) + BrO_3^- (aq) + 6 H^+ (aq) \rightarrow 3 Br_2 (aq) + 3 H_2 O (l)$.The rate of reaction is defined as the rat

Vedclass · Accepted Answer

$\frac{x}{5}$

Vedclass · Answer

(C) For the given reaction: $5 Br^- (aq) + BrO_3^- (aq) + 6 H^+ (aq) ightarrow 3 Br_2 (aq) + 3 H_2 O (l)$.The rate of reaction is defined as the rate of disappearance of a reactant divided by its stoichiometric coefficient.Rate $= -\frac{1}{5} \frac{\Delta[Br^-]}{\Delta t} = -\frac{\Delta[BrO_3^-]}{\Delta t} = -\frac{1}{6} \frac{\Delta[H^+]}{\Delta t} = \frac{1}{3} \frac{\Delta[Br_2]}{\Delta t} = \frac{1}{3} \frac{\Delta[H_2O]}{\Delta t}$.Given that $-\frac{\Delta[Br^-]}{\Delta t} = x \ mol \ L^{-1} \ min^{-1}$.Substituting this into the rate expression: Rate $= \frac{1}{5} 	imes x = \frac{x}{5} \ mol \ L^{-1} \ min^{-1}$.

$X = x$	$0$	$1$	$2$	$3$
$P(X = x)$	$\frac{1}{10}$	$\frac{2}{10}$	$\frac{3}{10}$	$\frac{4}{10}$

At $298 \ K$,the value of $-\frac{\Delta[Br^-]}{\Delta t}$ for the reaction $5 Br^- (aq) + BrO_3^- (aq) + 6 H^+ (aq) \rightarrow 3 Br_2 (aq) + 3 H_2 O (l)$ is $x \ mol \ L^{-1} \ min^{-1}$. What is the rate (in $mol \ L^{-1} \ min^{-1}$) of this reaction?

Similar Questions

If $e^{f(x)}=\frac{10+x}{10-x}, x \in(-10,10)$ and $f(x)=k f\left(\frac{200 x}{100+x^2}\right)$,then $k$ is equal to

Which one of the following reactions does not occur?

The probability distribution of a random variable $X$ is given below:
$X = x$ $0$ $1$ $2$ $3$
$P(X = x)$ $\frac{1}{10}$ $\frac{2}{10}$ $\frac{3}{10}$ $\frac{4}{10}$

Then the variance of $X$ is

$A$ body falling from a height of $10\,m$ rebounds from a hard floor. If it loses $20\%$ of its energy on impact,then the coefficient of restitution is:

Work done to increase the temperature of one mole of an ideal gas by $30^{\circ} C$,if it is expanding under the condition $V \propto T^{2/3}$ is,$(R = 8.314 \ J/mol \cdot K)$ (in $J$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module