A body falling from a height of 10,m rebounds | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the initial height be $h_1 = 10\,m$ and the rebound height be $h_2$.The initial potential energy is $PE_1 = mgh_1$.Since the body loses $20\%$

Vedclass · Accepted Answer

$0.89$

Vedclass · Answer

(A) Let the initial height be $h_1 = 10\,m$ and the rebound height be $h_2$.The initial potential energy is $PE_1 = mgh_1$.Since the body loses $20\%$ of its energy on impact,the remaining energy is $80\%$ of the initial energy.Thus,$mgh_2 = 0.80 	imes mgh_1$.This simplifies to $\frac{h_2}{h_1} = 0.8$.The coefficient of restitution $e$ is defined as the square root of the ratio of the rebound height to the initial height: $e = \sqrt{\frac{h_2}{h_1}}$.Substituting the value,$e = \sqrt{0.8} \approx 0.894$.Therefore,the coefficient of restitution is approximately $0.89$.

$A$ body falling from a height of $10\,m$ rebounds from a hard floor. If it loses $20\%$ of its energy on impact,then the coefficient of restitution is:

Similar Questions

The diameter of a plano-convex lens is $6 \ cm$ and its thickness at the center is $3 \ mm$. If the speed of light in the material of the lens is $2 \times 10^8 \ m/s$,the focal length of the lens is.......$cm$.

The type of bond connecting two nucleotides is

If the harmonic mean between the roots of $(5+\sqrt{2}) x^2-b x+(8+2 \sqrt{5})=0$ is $4$,then the value of $b$ is

$\lim _{x \rightarrow 0} \frac{\sin \left(\pi \cos ^2 x\right)}{x^2}$ is equal to

Lactose is a disaccharide of

Vedclass Test Series

Exam Paper Generator

Online Exam Module