At $25\,^{\circ}C$,the specific conductivity of a normal solution of $KCl$ is $0.002765\,S\,cm^{-1}$. The resistance of the cell is $400\,\Omega$. The cell constant is: (in $,cm^{-1}$)

Which among the following is the $CORRECT$ formula for the determination of cell constant?

The conductivity of $0.02 \ M$ solution of $AgNO_3$ is $0.00216 \ \Omega^{-1} \ cm^{-1}$ at $298 \ K$. What is its molar conductivity?

The limiting molar conductivities $\wedge ^0$ for $NaCl$,$KBr$,and $KCl$ are $126$,$152$,and $150 \ S \ cm^2 \ mol^{-1}$ respectively. The $\wedge ^0$ for $NaBr$ is ............ $S \ cm^2 \ mol^{-1}$.

Given the limiting molar conductivities at $25^{\circ}C$ for the following electrolytes in $S \, cm^{2} \, mol^{-1}$:
$KCl = 149.9$
$KNO_{3} = 145.0$
$HCl = 426.2$
$NaOAc = 91.0$
$NaCl = 126.5$
Calculate $\Lambda^{\infty}_{HOAc}$ using the Kohlrausch law of independent migration of ions.

For a strong electrolyte,a plot of molar conductivity against (concentration)$^{1/2}$ is a straight line,with a negative slope. The correct unit for the slope is: