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(B) The reaction involves the dissolution of the yellow precipitate of lead chromate $(PbCrO_4)$ in an excess of sodium hydroxide $(NaOH)$.$PbCrO_4$ i

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For precipitate dissolution reaction

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(B) The reaction involves the dissolution of the yellow precipitate of lead chromate $(PbCrO_4)$ in an excess of sodium hydroxide $(NaOH)$.$PbCrO_4$ is insoluble in water but reacts with excess $NaOH$ to form a soluble complex,sodium tetrahydroxoplumbate$(II)$ $(Na_2[Pb(OH)_4])$,and sodium chromate $(Na_2CrO_4)$.Since a solid precipitate is being converted into a soluble complex,this is a precipitate dissolution reaction.Therefore,the correct option is $B$.

Assign $A, B, C, D$ from the given type of reaction.
$PbCrO_4 \downarrow + 4NaOH \,(Excess) \longrightarrow Na_2[Pb(OH)_4] + Na_2CrO_4$

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Assign $A, B, C, D$ from the given type of reaction.$PbCrO_4 \downarrow + 4NaOH \,(Excess) \longrightarrow Na_2[Pb(OH)_4] + Na_2CrO_4$