Assertion : The major products formed by heat | vedclass

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Question

(A) The reaction of $C_6H_5CH_2OCH_3$ with $HI$ proceeds via an $S_N1$ mechanism because the benzyl carbocation $(C_6H_5CH_2^+)$ is highly stable due

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If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) The reaction of $C_6H_5CH_2OCH_3$ with $HI$ proceeds via an $S_N1$ mechanism because the benzyl carbocation $(C_6H_5CH_2^+)$ is highly stable due to resonance.The cleavage of the $C-O$ bond occurs such that the more stable carbocation is formed.Since the benzyl carbocation is more stable than the methyl carbocation $(CH_3^+)$,the iodide ion attacks the benzyl group to form $C_6H_5CH_2I$,while the methoxide group is protonated to form $CH_3OH$.Therefore,both the Assertion and the Reason are correct,and the Reason is the correct explanation of the Assertion.

Assertion : The major products formed by heating $C_6H_5CH_2OCH_3$ with $HI$ are $C_6H_5CH_2I$ and $CH_3OH$.
Reason : Benzyl cation is more stable than methyl cation.

Similar Questions

In which case is methyl $t$-butyl ether formed?

Give $IUPAC$ names of the following ethers:
$(i)$ $C_2H_5OCH_2CH(CH_3)_2$
$(ii)$ $CH_3OCH_2CH_2Cl$
$(iii)$ $O_2NC_6H_4OCH_3(p)$
$(iv)$ $CH_3CH_2CH_2OCH_3$
$(v)$ $1$-Ethoxy-$4,4$-dimethylcyclohexane
$(vi)$ Ethoxybenzene

At $525 \ K$,aromatic ethers do not undergo cleavage by $HI$. Which of the following compounds will not undergo cleavage?

Which of the following compounds has no reaction with sodium metal?

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Assertion : The major products formed by heating $C_6H_5CH_2OCH_3$ with $HI$ are $C_6H_5CH_2I$ and $CH_3OH$.Reason : Benzyl cation is more stable than methyl cation.