Assertion : Greater the value of van der Waal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The van der Waal's constant $a$ represents the magnitude of intermolecular attractive forces in a gas. Higher values of $a$ indicate stronger attr

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) The van der Waal's constant $a$ represents the magnitude of intermolecular attractive forces in a gas. Higher values of $a$ indicate stronger attractive forces between gas molecules,which makes it easier for the gas to be liquefied. In the van der Waal's equation,the pressure correction term is $\frac{an^2}{V^2}$,where $a$ accounts for these attractive forces. Therefore,both the assertion and the reason are correct,and the reason is the correct explanation of the assertion.

Gas	$Ar$	$Ne$	$Kr$	$Xe$
$a / (atm \ dm^6 \ mol^{-2})$	$1.3$	$0.2$	$5.1$	$4.1$
$b / (10^{-2} \ dm^3 \ mol^{-1})$	$3.2$	$1.7$	$1.0$	$5.0$

Assertion : Greater the value of van der Waal's constant $a$,greater is the liquefaction of gas.
Reason : $a$ indirectly measures the magnitude of attractive forces between the molecules.

Similar Questions

At very high pressures,the compressibility factor of one mole of a gas is given by

The correction factor '$a$' in the van der Waals equation for real gases corresponds to:

Gases deviate from ideal behaviour at high pressures because the gas molecules

Consider the van der Waals constants,$a$ and $b$,for the following gases:

Gas $Ar$ $Ne$ $Kr$ $Xe$

$a / (atm \ dm^6 \ mol^{-2})$ $1.3$ $0.2$ $5.1$ $4.1$

$b / (10^{-2} \ dm^3 \ mol^{-1})$ $3.2$ $1.7$ $1.0$ $5.0$

Which gas is expected to have the highest critical temperature?

Explain the physical significance of van der Waals parameters.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Greater the value of van der Waal's constant $a$,greater is the liquefaction of gas. Reason : $a$ indirectly measures the magnitude of attractive forces between the molecules.