Assertion : Acetamide reacts with Br_2 in pre | vedclass

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Question

(A) The reaction of acetamide $(CH_3CONH_2)$ with $Br_2$ in the presence of a base like $CH_3ONa$ is a variation of the Hofmann bromamide degradation.

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If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) The reaction of acetamide $(CH_3CONH_2)$ with $Br_2$ in the presence of a base like $CH_3ONa$ is a variation of the Hofmann bromamide degradation.In this specific medium,the intermediate formed is methyl isocyanate $(CH_3-N=C=O)$.This methyl isocyanate then undergoes nucleophilic attack by the methanol $(CH_3OH)$ present in the medium to form methyl $N$-methylcarbamate $(CH_3NHCOOCH_3)$.Therefore,both the Assertion and the Reason are correct,and the Reason correctly explains the mechanism of the reaction.

Assertion : Acetamide reacts with $Br_2$ in presence of methanolic $CH_3ONa$ to form methyl $N$-methylcarbamate.
Reason : Methyl isocyanate is formed as an intermediate which reacts with methanol to form methyl $N$-methylcarbamate.

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Assertion : Acetamide reacts with $Br_2$ in presence of methanolic $CH_3ONa$ to form methyl $N$-methylcarbamate.Reason : Methyl isocyanate is formed as an intermediate which reacts with methanol to form methyl $N$-methylcarbamate.