As shown in the figure,charges +q, +q, -q and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Point '$A$' is at a distance $l$ from the top $+q$ charge and the bottom $+q$ charge.The distance from point '$A$' to both $-q$ charges is $\sqrt{

Vedclass · Accepted Answer

$\frac{2kq}{l}[1-\frac{1}{\sqrt{5}}]$

Vedclass · Answer

(D) Point '$A$' is at a distance $l$ from the top $+q$ charge and the bottom $+q$ charge.The distance from point '$A$' to both $-q$ charges is $\sqrt{(2l)^2 + l^2} = \sqrt{4l^2 + l^2} = \sqrt{5l^2} = l\sqrt{5}$.The electric potential $V$ at point '$A$' due to all four charges is given by the sum of potentials from each charge:$V_A = k(\frac{q}{l} + \frac{q}{l} - \frac{q}{l\sqrt{5}} - \frac{q}{l\sqrt{5}})$$V_A = k(\frac{2q}{l} - \frac{2q}{l\sqrt{5}})$$V_A = \frac{2kq}{l}(1 - \frac{1}{\sqrt{5}})$Therefore,option $(D)$ is correct.

As shown in the figure,charges $+q, +q, -q$ and $-q$ are placed on the vertices of a square,each side length is $2l$. The electric potential at the mid-point '$A$' of the charges $+q$ and $+q$ is . . . . . . .

Similar Questions

The energy which an $e^-$ acquires when accelerated through a potential difference of $1 \, V$ is called:

Which of the following correctly represents the variation of electric potential $(V)$ of a charged spherical conductor of radius $(R)$ with radial distance $(r)$ from the centre?

Write an expression for the potential at a point outside a uniformly charged spherical shell,on the surface,and inside the shell.

Three concentric metallic spherical shells $A, B,$ and $C$ of radii $a, b,$ and $c$ $(a < b < c)$ have surface charge densities $-\sigma, +\sigma,$ and $-\sigma$ respectively. The potential of shell $A$ is:

At the centre of a half ring of radius $R=10 \ cm$ and linear charge density $\lambda = 4 \ nC \ m^{-1}$,the potential is $x \pi \ V$. The value of $x$ is . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module