As shown in the figure,AB,AC and overleftrigh | vedclass

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(C) Let the tangent $\overleftrightarrow{PQ}$ touch the circle at point $R$.Since the lengths of tangents drawn from an external point to a circle are

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(C) Let the tangent $\overleftrightarrow{PQ}$ touch the circle at point $R$.Since the lengths of tangents drawn from an external point to a circle are equal,we have:$PB = PR$ and $QC = QR$.The perimeter of $\Delta APQ = AP + PQ + AQ$.$= AP + (PR + RQ) + AQ$.$= AP + PB + QC + AQ$ (since $PR = PB$ and $RQ = QC$).$= (AP + PB) + (AQ + QC)$.$= AB + AC$.Since $AB = AC$ (tangents from an external point $A$),we have $AB = AC = 6$.Therefore,the perimeter of $\Delta APQ = 6 + 6 = 12$.

As shown in the figure,$AB$,$AC$ and $\overleftrightarrow{PQ}$ are tangents to the circle. If $AB = 6$,then the perimeter of $\Delta APQ = \ldots \ldots \ldots$.

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