The correct order of radii is

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(B) For isoelectronic species,the ionic radius increases as the nuclear charge (atomic number) decreases. In the series $F^{-}$,$O^{2-}$,and $N^{3-}$,

Vedclass · Accepted Answer

$F^{-} < O^{2-} < N^{3-}$

Vedclass · Answer

(B) For isoelectronic species,the ionic radius increases as the nuclear charge (atomic number) decreases. In the series $F^{-}$,$O^{2-}$,and $N^{3-}$,all have $10$ electrons. The atomic numbers are $F (9)$,$O (8)$,and $N (7)$. Since the nuclear charge decreases from $F$ to $N$,the attraction on the electrons decreases,and the ionic radius increases. Therefore,the correct order is $F^{-} < O^{2-} < N^{3-}$.

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