Arrange the following in order of their leavi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The leaving group ability is inversely proportional to the basicity of the group. $A$ weaker base is a better leaving group. The basicity is deter

Vedclass · Accepted Answer

$I > II > IV > III$

Vedclass · Answer

(C) The leaving group ability is inversely proportional to the basicity of the group. $A$ weaker base is a better leaving group. The basicity is determined by the strength of the conjugate acid. Conjugate acids are: $HBr$ $(pK_a \approx -9)$,$CH_3COOH$ $(pK_a \approx 4.76)$,$PhOH$ $(pK_a \approx 10)$,and $CH_3CH_2OH$ $(pK_a \approx 16)$. The order of acid strength is: $HBr > CH_3COOH > PhOH > CH_3CH_2OH$. Therefore,the order of basicity is: $Br^{-} Since the leaving group tendency is the reverse of basicity,the order is: $Br^{-} > CH_3COO^{-} > PhO^{-} > CH_3CH_2O^{-}$,which corresponds to $I > II > IV > III$.

Arrange the following in order of their leaving group tendency:
$(I) Br^{-}$,$(II) CH_3COO^{-}$,$(III) CH_3CH_2O^{-}$,$(IV) PhO^{-}$

Similar Questions

The major product of the following reaction is:

Which one of the following is more reactive towards $S_{N}2$ reaction?

The major product of the reaction is:

$C_6H_{13}Br + OH^{-} \to C_6H_{13}OH + Br^{-}$ is an example of

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following in order of their leaving group tendency: $(I) Br^{-}$,$(II) CH_3COO^{-}$,$(III) CH_3CH_2O^{-}$,$(IV) PhO^{-}$