The major product of the reaction is:

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(C) The reaction is an $E2$ elimination reaction,which requires an anti-periplanar arrangement of the leaving group $(-Br)$ and the $\beta$-hydrogen a

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(C) The reaction is an $E2$ elimination reaction,which requires an anti-periplanar arrangement of the leaving group $(-Br)$ and the $\beta$-hydrogen atom. In the given Fischer projection,the $-Br$ and $-H$ are on the same side (syn-periplanar). To undergo $E2$ elimination,the molecule must rotate around the $C-C$ single bond to bring the $-Br$ and $-H$ into an anti-periplanar conformation. Upon rotation,the two phenyl $(Ph)$ groups will be on opposite sides of the double bond in the resulting alkene,leading to the formation of the trans-isomer as the major product.

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