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(C) The reactivity of alkyl halides towards $E_2$ reaction depends on the stability of the transition state,which is influenced by the stability of th

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$z > y > x$

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(C) The reactivity of alkyl halides towards $E_2$ reaction depends on the stability of the transition state,which is influenced by the stability of the alkene formed.$E_2$ reaction involves the abstraction of a $\beta$-hydrogen and the elimination of a leaving group in a single step.As the number of alkyl groups attached to the double-bonded carbons increases,the stability of the resulting alkene increases due to hyperconjugation and inductive effects.$(x)$ $CH_3-CH_2-CH_2-Br$ is a primary $(1^{\circ})$ alkyl halide,which forms a monosubstituted alkene.$(y)$ $CH_3-CH(Br)-CH_3$ is a secondary $(2^{\circ})$ alkyl halide,which forms a disubstituted alkene.$(z)$ $(CH_3)_3C-Br$ is a tertiary $(3^{\circ})$ alkyl halide,which forms a trisubstituted alkene.Since the stability of the alkene follows the order: trisubstituted > disubstituted > monosubstituted,the reactivity towards $E_2$ follows the order: $3^{\circ} > 2^{\circ} > 1^{\circ}$.Therefore,the correct order is $z > y > x$.

Arrange the following compounds in decreasing order of reactivity towards $E_2$ reaction:
$(x)$ $CH_3-CH_2-CH_2-Br$
$(y)$ $CH_3-CH(Br)-CH_3$
$(z)$ $(CH_3)_3C-Br$

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Arrange the following compounds in decreasing order of reactivity towards $E_2$ reaction:$(x)$ $CH_3-CH_2-CH_2-Br$$(y)$ $CH_3-CH(Br)-CH_3$$(z)$ $(CH_3)_3C-Br$