Major products A and B formed in the followin | vedclass

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Question

(B) Step $1$: Reaction of $2$-methylcyclohexanol with $PBr_3$ leads to the formation of $1$-bromo-$2$-methylcyclohexane $(A)$ via an $S_N2$ mechanism.

Vedclass · Accepted Answer

$A = 	ext{1-bromo-2-methylcyclohexane}; B = 	ext{1-methylcyclohexene}$

Vedclass · Answer

(B) Step $1$: Reaction of $2$-methylcyclohexanol with $PBr_3$ leads to the formation of $1$-bromo-$2$-methylcyclohexane $(A)$ via an $S_N2$ mechanism.Step $2$: Treatment of $1$-bromo-$2$-methylcyclohexane $(A)$ with alcoholic $KOH$ (a strong base) results in dehydrohalogenation via an $E2$ mechanism.Step $3$: According to Zaitsev's rule,the more substituted alkene is the major product. The base abstracts a proton from the $C_2$ position,leading to the formation of $1$-methylcyclohexene $(B)$ as the major product.

Major products $A$ and $B$ formed in the following reaction sequence are:

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