Arrange the following according to the instructions:
$(i)$ Arrange in descending order of acidic strength:
$CH_3COOH, (CH_3)_3CCOOH, (CH_3)_2CHCOOH, CH_3CH_2COOH$
(ii) Arrange in descending order of stability:
$\stackrel{+}{CH}_3, (CH_3)_3\stackrel{+}{C}, CH_3CH_2^+, (CH_3)_2\stackrel{+}{CH}$
(iii) Arrange in increasing order of acidic strength:
$CCl_3COOH, CH_3COOH, CHCl_2COOH, CH_2ClCOOH$
(iv) Arrange in increasing order of stability:
$(a)$ $CH_3CH=CH-CHO$
$(b)$ $CH_3\stackrel{+}{CH}-CH=C-O:^-$
$(c)$ $\stackrel{+}{CH}_2-CH=CH-C=O$
$(v)$ Arrange in decreasing order of stability:
$(I)$ $CH_2=CH-CHO$
$(II)$ $\stackrel{+}{CH}_2-CH=C-H$ (with $O^-$)
$(III)$ $:CH_2-CH=C-H$ (with $O^-$)

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(A) $(i)$ Acidic strength decreases as the electron-donating inductive effect $(+I)$ of alkyl groups increases: $CH_3COOH > CH_3CH_2COOH > (CH_3)_2CHCOOH > (CH_3)_3CCOOH$
(ii) Stability of carbocations increases with the number of alkyl groups attached due to hyperconjugation and $+I$ effect: $(CH_3)_3\stackrel{+}{C} > (CH_3)_2\stackrel{+}{CH} > CH_3CH_2^+ > \stackrel{+}{CH}_3$
(iii) Acidic strength increases with the number of electron-withdrawing chlorine atoms: $CH_3COOH < CH_2ClCOOH < CHCl_2COOH < CCl_3COOH$
(iv) Stability order based on resonance and charge separation: $(c) < (b) < (a)$
$(v)$ Stability order based on resonance structures: $(I) > (II) > (III)$

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