Polarisation of electrons in acrolein may be | vedclass

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(B) Acrolein is $CH_2 = CH - CHO$.The oxygen atom is more electronegative than the carbon atom,so the $\pi$-electrons of the $C=O$ bond shift towards

Vedclass · Accepted Answer

$CH_2^{\delta +} = CH - CH = O^{\delta -}$

Vedclass · Answer

(B) Acrolein is $CH_2 = CH - CHO$.The oxygen atom is more electronegative than the carbon atom,so the $\pi$-electrons of the $C=O$ bond shift towards the oxygen atom,giving it a partial negative charge $(\delta-)$ and the carbonyl carbon a partial positive charge $(\delta+)$.Due to the conjugation of the $C=C$ double bond with the $C=O$ double bond,this positive charge is delocalized,resulting in the terminal $CH_2$ group acquiring a partial positive charge $(\delta+)$.Thus,the correct polarisation is $CH_2^{\delta+} = CH - CH = O^{\delta-}$.

Polarisation of electrons in acrolein may be written as:

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