Polarisation of electrons in acroline may be | vedclass

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Question

Polarisation of electrons in acrolein may be written as $\stackrel{+\delta}{CH _2}= CH - CH =\stackrel{-\delta}{ O }$.

$O$ atom is more EN than $C$

Vedclass · Accepted Answer

$CH_2^{\delta + } = CH - CH = {O^{\delta - }}$

Vedclass · Answer

Polarisation of electrons in acrolein may be written as $\stackrel{+\delta}{CH _2}= CH - CH =\stackrel{-\delta}{ O }$.

$O$ atom is more EN than $C$ atom, so it acquires $(-\delta)$ charge and $C$ atom acquires $(+\delta)$ charge which is transferred to the last $C$ atom.

Polarisation of electrons in acroline may be written as

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