Identify the most stable free radical from th | vedclass

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(B) The stability of free radicals is determined by the number of alkyl groups attached to the carbon atom bearing the odd electron,due to the inducti

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$(CH_3)_3C\cdot$

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(B) The stability of free radicals is determined by the number of alkyl groups attached to the carbon atom bearing the odd electron,due to the inductive effect and hyperconjugation.The order of stability of alkyl free radicals is: $Tertiary (3^{\circ}) > Secondary (2^{\circ}) > Primary (1^{\circ}) > Methyl (CH_3\cdot)$.$1$. $(CH_3)_3C\cdot$ is a tertiary $(3^{\circ})$ free radical,which is stabilized by $9$ hyperconjugative structures.$2$. $(CH_3)_2CH\cdot$ is a secondary $(2^{\circ})$ free radical,which is stabilized by $6$ hyperconjugative structures.$3$. $CH_3-CH_2\cdot$ is a primary $(1^{\circ})$ free radical,which is stabilized by $3$ hyperconjugative structures.$4$. $CH_3\cdot$ is a methyl free radical,which has no hyperconjugative stabilization.Therefore,the tertiary free radical $(CH_3)_3C\cdot$ is the most stable.

Identify the most stable free radical from the following.

Similar Questions

Which of the following carbocations is the most stable?

The order of stability of the following carbocations is:
$I$. $CH_2 = CH - CH_2^+$
$II$. $CH_3 - CH_2 - CH_2^+$
$III$. $C_6H_5CH_2^+$

The shape of a carbonium ion (carbocation) is:

What is the order of stability of the following carbocations?
$(X). CH_3 - \overset{\oplus}{C}H - CH_3$
$(Y). CH_3 - \overset{\oplus}{C}H - OCH_3$
$(Z). CH_3 - \overset{\oplus}{C}H - COCH_3$

Which of the following is the most stable free radical?

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