Area of the largest triangle that can be inscribed in a semi-circle of radius $r$ units is
Area of the largest triangle that can be inscribed in a semi-circle of radius $r$ units is
- A
$\frac{1}{2} r^{2}$ sq. units
- B
$r^{2}$ sq. units
- C
$2 r^{2}$ sq. units
- D
$\sqrt{2} r^{2}$ sq. units
Similar Questions
If the radius of a circle is doubled, its area becomes $\ldots \ldots \ldots .$ times the area of the original circle.
If the radius of a circle is doubled, its area becomes $\ldots \ldots \ldots .$ times the area of the original circle.
As shown in the diagram, $\overline{ AC }$ is a diameter of the circle with centre O. $\Delta ABC$ is inscribed in a semicircle of the circle. If $AC =35 \,cm$, $AB =21\, cm$ and $BC =28\, cm ,$ find the area of the shaded region. (in $cm^2$)
As shown in the diagram, $\overline{ AC }$ is a diameter of the circle with centre O. $\Delta ABC$ is inscribed in a semicircle of the circle. If $AC =35 \,cm$, $AB =21\, cm$ and $BC =28\, cm ,$ find the area of the shaded region. (in $cm^2$)
In $\odot( O , r),$ the length of minor $\widehat{ ACB }$ is one-eighth of the circumference of the circle. Then, the measure of the angle subtended at the centre by that arc is $\ldots \ldots \ldots \ldots$
In $\odot( O , r),$ the length of minor $\widehat{ ACB }$ is one-eighth of the circumference of the circle. Then, the measure of the angle subtended at the centre by that arc is $\ldots \ldots \ldots \ldots$
If the sum of the circumferences of two circles with radii $R_{1}$ and $R_{2}$ is equal to the circumference of a circle of radius $R ,$ then
If the sum of the circumferences of two circles with radii $R_{1}$ and $R_{2}$ is equal to the circumference of a circle of radius $R ,$ then
In a circle with radius $20 \,cm$, the measures of the angle subtended at the centre for two distinct sectors are $15$ and $90 .$ Then, the ratio of the areas of those sectors is $\ldots \ldots \ldots .$
In a circle with radius $20 \,cm$, the measures of the angle subtended at the centre for two distinct sectors are $15$ and $90 .$ Then, the ratio of the areas of those sectors is $\ldots \ldots \ldots .$