Aqueous sulphite reacts with dilute sulphuric acid to form $X_{(g)}$. The liberated $X_{(g)}$ is passed into acidified $KMnO_4$ solution. What is the oxidation state of $Mn$ in the product formed?

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below:
$\frac{1}{2} Cl_{2(g)}$ $\xrightarrow{\frac{1}{2} \Delta_{diss} H^{\Theta}} Cl_{(g)}$ $\xrightarrow{\Delta_{eg} H^{\Theta}} Cl^{-}_{(g)}$ $\xrightarrow{\Delta_{Hyd} H^{\Theta}} Cl^{-}_{(aq)}$
(using the data,$\Delta_{diss} H_{Cl_2}^{\Theta} = 240 \ kJ \ mol^{-1}$,$\Delta_{eg} H_{Cl}^{\Theta} = -349 \ kJ \ mol^{-1}$,$\Delta_{Hyd} H_{Cl}^{\Theta} = -381 \ kJ \ mol^{-1}$) will be ............. $kJ \ mol^{-1}$.

$2 \text{ mol}$ of $FeSO_4$ are oxidized by $X \text{ mol}$ of $KMnO_4$ whereas $2 \text{ mol}$ of $FeC_2O_4$ are oxidized by $Y \text{ mol}$ of $KMnO_4$. The ratio of $X$ and $Y$ is:

Which of the following can act both as an oxidizing and a reducing agent?

Balance the following redox reactions using the oxidation number and ion-electron method:
$(1) \ Zn + NO_3^- + H^+ \to Zn^{2+} + N_2O + H_2O$
$(2) \ I^- + O_2 + H_2O \to I_2 + OH^-$
$(3) \ MnO_4^- + C_2H_5OH \to Mn^{2+} + CH_3COOH$

The oxidation state of copper changes when aqueous copper $(II)$ ions react with
$(I)$ $NaOH_{(aq)}$
$(II)$ $Fe_{(s)}$
$(III)$ $KI_{(aq)}$