Aqueous solution of HCl has the pH = 4. Its m | vedclass

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(C) The $pH$ of a solution is defined as $pH = -\log[H^{+}]$.Given $pH = 4$,we have $4 = -\log[H^{+}]$,which implies $[H^{+}] = 10^{-4} \, M$.Since $H

Vedclass · Accepted Answer

$0.0001$

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(C) The $pH$ of a solution is defined as $pH = -\log[H^{+}]$.Given $pH = 4$,we have $4 = -\log[H^{+}]$,which implies $[H^{+}] = 10^{-4} \, M$.Since $HCl$ is a strong acid,it dissociates completely in water as $HCl \rightarrow H^{+} + Cl^{-}$.Therefore,the molarity of the $HCl$ solution is equal to the concentration of $H^{+}$ ions,which is $10^{-4} \, M$ or $0.0001 \, M$.

Aqueous solution of $HCl$ has the $pH = 4$. Its molarity would be (in $, M$)

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