The pH of a 10^{-10} M NaOH solution is app | vedclass

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Question

(B) For a very dilute base solution like $10^{-10} \ M \ NaOH$,the contribution of $OH^-$ ions from the auto-ionization of water cannot be neglected.

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) For a very dilute base solution like $10^{-10} \ M \ NaOH$,the contribution of $OH^-$ ions from the auto-ionization of water cannot be neglected. The total $[OH^-] = [OH^-]_{	ext{base}} + [OH^-]_{	ext{water}} = 10^{-10} + 10^{-7} \approx 10^{-7} \ M$. Thus,$pOH = -\log(10^{-7}) = 7$. Since $pH + pOH = 14$,we get $pH = 14 - 7 = 7$. Therefore,the $pH$ of the solution is approximately $7$.

The $pH$ of a $10^{-10} \ M \ NaOH$ solution is approximately......

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