Aniline with solid KOH and CS_2 gives : | vedclass

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(D) The reaction of aniline $(C_6H_5NH_2)$ with carbon disulfide $(CS_2)$ in the presence of solid potassium hydroxide $(KOH)$ is known as the Hofmann

Vedclass · Accepted Answer

Diphenyl thio-urea

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(D) The reaction of aniline $(C_6H_5NH_2)$ with carbon disulfide $(CS_2)$ in the presence of solid potassium hydroxide $(KOH)$ is known as the Hofmann mustard oil reaction. In this reaction,aniline reacts with $CS_2$ to form a dithiocarbamate intermediate,which upon heating with $KOH$ decomposes to form phenyl isothiocyanate $(C_6H_5NCS)$. However,if the reaction is carried out under specific conditions or if the intermediate is treated further,it can lead to the formation of $N,N'$-diphenylthiourea $(C_6H_5NH-CS-NHC_6H_5)$. Given the options,$N,N'$-diphenylthiourea is the standard product formed in this specific chemical transformation.

Aniline with solid $KOH$ and $CS_2$ gives :

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