Which of the following is the most basic?

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(D) The basicity of an anion is inversely proportional to the stability of its conjugate acid. The conjugate acids are $CH_4$ $(sp^3)$,$CH_2=CH_2$ $(s

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$CH_3-CH_2^\ominus$

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(D) The basicity of an anion is inversely proportional to the stability of its conjugate acid. The conjugate acids are $CH_4$ $(sp^3)$,$CH_2=CH_2$ $(sp^2)$,$CH \equiv CH$ $(sp)$,and $CH_3-CH_3$ $(sp^3)$. The acidity of these conjugate acids follows the order: $CH \equiv CH > CH_2=CH_2 > CH_3-CH_3 \approx CH_4$. Since $CH_3-CH_3$ is a slightly weaker acid than $CH_4$ due to the $+I$ effect of the alkyl group,its conjugate base $CH_3-CH_2^\ominus$ is more basic than $CH_3^\ominus$. Thus,the order of basicity is $CH_3-CH_2^\ominus > CH_3^\ominus > CH_2=CH^\ominus > CH \equiv C^\ominus$.

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