Angles of a quadrilateral are in the ratio 3: | vedclass

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(A) Let the angles of the quadrilateral be $3x, 4x, 4x,$ and $7x$.The sum of the angles of a quadrilateral is $360^{\circ}$.Therefore,$3x + 4x + 4x +

Vedclass · Accepted Answer

$60^{\circ}, 80^{\circ}, 80^{\circ}, 140^{\circ}$

Vedclass · Answer

(A) Let the angles of the quadrilateral be $3x, 4x, 4x,$ and $7x$.The sum of the angles of a quadrilateral is $360^{\circ}$.Therefore,$3x + 4x + 4x + 7x = 360^{\circ}$.$18x = 360^{\circ}$.$x = \frac{360^{\circ}}{18} = 20^{\circ}$.Now,calculate the individual angles:First angle $= 3 	imes 20^{\circ} = 60^{\circ}$.Second angle $= 4 	imes 20^{\circ} = 80^{\circ}$.Third angle $= 4 	imes 20^{\circ} = 80^{\circ}$.Fourth angle $= 7 	imes 20^{\circ} = 140^{\circ}$.Thus,the angles are $60^{\circ}, 80^{\circ}, 80^{\circ},$ and $140^{\circ}$.

Angles of a quadrilateral are in the ratio $3:4:4:7$. Find all the angles of the quadrilateral.

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