An organic compound A contains nitrogen and c | vedclass

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Question

(A) $1$. The compound $A$ contains $N$ and $Cl$ and forms an acidic solution in water,suggesting it is an amine hydrochloride salt $(R-NH_3^+Cl^-)$.$2

Vedclass · Accepted Answer

$C_6H_5NH_3Cl$

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(A) $1$. The compound $A$ contains $N$ and $Cl$ and forms an acidic solution in water,suggesting it is an amine hydrochloride salt $(R-NH_3^+Cl^-)$.$2$. The molecular weight of $C_6H_5NH_3Cl$ is $77 + 14 + 3 + 35.5 = 129.5$,which matches the given $131 \pm 2$.$3$. Treatment with $NaOH$ releases the free amine: $C_6H_5NH_3Cl + NaOH \rightarrow C_6H_5NH_2 + NaCl + H_2O$. The liquid $C_6H_5NH_2$ (aniline) contains $N$ but no $Cl$.$4$. Aniline reacts with nitrous acid $(HNO_2)$ at $0-5^{\circ}C$ to form benzenediazonium chloride,which then couples with phenol in basic medium to form $p$-hydroxyazobenzene,an orange dye.$5$. Thus,$A$ is $C_6H_5NH_3Cl$ (anilinium chloride).

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$p$-Toluidine reacts with benzene diazonium chloride to form a compound,which on boiling with $aq. H_2SO_4$ gives ........ products.

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Give a plausible explanation for each of the following:
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Which among the following represents reagent $A$ in the given reaction?
$C_6H_5N_2^+Cl^- + A \xrightarrow{NaOH} \text{Product (Orange-red dye)}$

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