$p$-Toluidine reacts with benzene diazonium chloride to form a compound,which on boiling with $aq. H_2SO_4$ gives ........ products.

  • A
    $3$
  • B
    $2$
  • C
    $4$
  • D
    $5$

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$CH_3CH_2CONH_2$ $\xrightarrow{Br_2 / KOH_{(aq)}} X$ $\xrightarrow{C_6H_5COCl} Y$. Which statement is true?

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Give the structures of $A$,$B$ and $C$ in the following reactions:
$(i)$ $CH_3CH_2I$ $\xrightarrow{NaCN} A$ $\xrightarrow[Partial\,hydrolysis]{OH^{-}} B$ $\xrightarrow{NaOH+Br_2} C$
$(ii)$ $C_6H_5N_2Cl$ $\xrightarrow{CuCN} A$ $\xrightarrow{H_2O/H^{+}} B$ $\xrightarrow[\Delta]{NH_3} C$
$(iii)$ $CH_3CH_2Br$ $\xrightarrow{KCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow[0\ ^oC]{HNO_2} C$
$(iv)$ $C_6H_5NO_2$ $\xrightarrow{Fe/HCl} A$ $\xrightarrow[273\ K]{NaNO_2+HCl} B$ $\xrightarrow[\Delta]{H_2O/H^{+}} C$
$(v)$ $CH_3COOH$ $\xrightarrow[\Delta]{NH_3} A$ $\xrightarrow{NaOBr} B$ $\xrightarrow{NaNO_2/HCl} C$
$(vi)$ $C_6H_5NO_2$ $\xrightarrow{Fe/HCl} A$ $\xrightarrow[273\ K]{HNO_2} B$ $\xrightarrow{C_6H_5OH} C$

The product $(A)$ is:

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Match the following:
List-$I$List-$II$
$A$. Amide$I$. Carbylamine reaction
$B$. Nitrile$II$. Hinsberg's reagent
$C$. $C_6H_5SO_2Cl$$III$. Hofmann's bromamide reaction
$D$. $1^{\circ}$-Amine$IV$. $LiAlH_4$

Amine compounds exhibit ............ isomerism.

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