An organic compound 'A' (C_9H_{10}O) when tre | vedclass

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(B) The reaction of the ether $'A'$ $(C_9H_{10}O)$ with conc. $HI$ leads to cleavage.Compound $'A'$ is benzyl vinyl ether $(C_6H_5CH_2-O-CH=CH_2)$.Upo

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(B) The reaction of the ether $'A'$ $(C_9H_{10}O)$ with conc. $HI$ leads to cleavage.Compound $'A'$ is benzyl vinyl ether $(C_6H_5CH_2-O-CH=CH_2)$.Upon treatment with $HI$,the ether bond cleaves to form benzyl iodide ($C_6H_5CH_2I$,compound $'B'$) and vinyl alcohol ($CH_2=CHOH$,compound $'C'$).Compound $'B'$ $(C_6H_5CH_2I)$ reacts with $AgNO_3$ to give a yellow precipitate of $AgI$.Compound $'C'$ $(CH_2=CHOH)$ is unstable and tautomerizes to acetaldehyde ($CH_3CHO$,compound $'D'$).Acetaldehyde $(CH_3CHO)$ gives a positive iodoform test because it contains the $CH_3CO-$ group.Therefore,the structure of $'A'$ is benzyl vinyl ether.

Column-$I$	Column-$II$
$(A)$ $CH_3-O-CH_3$	$(1)$ $C_6H_5OH + CH_3I$
$(B)$ $(CH_3)_2CH-O-CH_3$	$(2)$ $(CH_3)_3C-I + CH_3OH$
$(C)$ $(CH_3)_3C-O-CH_3$	$(3)$ $C_6H_5I + CH_3OH$
$(D)$ $C_6H_5-O-CH_3$	$(4)$ $CH_3OH + CH_3I$
	$(5)$ $(CH_3)_2CHOH + CH_3I$
	$(6)$ $(CH_3)_2CH-I + CH_3OH$
	$(7)$ $(CH_3)_3COH + CH_3I$

An organic compound $'A'$ $(C_9H_{10}O)$ when treated with conc. $HI$ undergoes cleavage to yield compounds $'B'$ and $'C'$. $'B'$ gives a yellow precipitate with $AgNO_3$ whereas $'C'$ tautomerizes to $'D'$. $'D'$ gives a positive iodoform test. $'A'$ could be :

Similar Questions

This reaction,$CH_3-C(CH_3)_2-ONa + CH_3-CH_2-Cl \xrightarrow{-NaCl} CH_3-C(CH_3)_2-O-CH_2-CH_3$ is called:

Which one of the following,with $HBr$ will give a phenol?

Assertion : The major products formed by heating $C_6H_5CH_2OCH_3$ with $HI$ are $C_6H_5CH_2I$ and $CH_3OH$.
Reason : Benzyl cation is more stable than methyl cation.

Write equations of the following reactions:
$(i)$ Friedel-Crafts reaction - alkylation of anisole.
$(ii)$ Nitration of anisole.
$(iii)$ Bromination of anisole in ethanoic acid medium.
$(iv)$ Friedel-Craft's acetylation of anisole.

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