An open pipe of length 33 cm resonates to a | vedclass

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(B) The fundamental frequency $(f_1)$ of an open pipe is given by $f_1 = \frac{v}{2L}$.Given $v = 330 \ m/s$ and $L = 33 \ cm = 0.33 \ m$.$f_1 = \frac

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The $2^{nd}$ harmonic

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(B) The fundamental frequency $(f_1)$ of an open pipe is given by $f_1 = \frac{v}{2L}$.Given $v = 330 \ m/s$ and $L = 33 \ cm = 0.33 \ m$.$f_1 = \frac{330}{2 	imes 0.33} = \frac{330}{0.66} = 500 \ Hz$.The frequency of the $n^{th}$ harmonic is given by $f_n = n 	imes f_1$.Given $f_n = 1000 \ Hz$,we have $1000 = n 	imes 500$.Therefore,$n = 2$.This corresponds to the $2^{nd}$ harmonic.

An open pipe of length $33 \ cm$ resonates to a frequency of $1000 \ Hz$. The mode of vibration is: (velocity of sound $= 330 \ m/s$)

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