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Question

(B) The process occurs at constant temperature,so the change in internal energy $\Delta U$ is equal to the heat supplied $Q$.Initial state: $4 \, mole

Vedclass · Accepted Answer

$Q = RT$

Vedclass · Answer

(B) The process occurs at constant temperature,so the change in internal energy $\Delta U$ is equal to the heat supplied $Q$.Initial state: $4 \, moles$ of diatomic gas $(F = 5)$.Initial internal energy $U_i = 4 	imes \frac{5}{2} RT = 10RT$.Final state: $2 \, moles$ of diatomic gas remain,and $2 \, moles$ of diatomic gas dissociate into $4 \, moles$ of monoatomic gas $(F = 3)$.Final internal energy $U_f = (2 	imes \frac{5}{2} RT) + (4 	imes \frac{3}{2} RT) = 5RT + 6RT = 11RT$.Heat supplied $Q = \Delta U = U_f - U_i = 11RT - 10RT = RT$.

An insulated container contains $4 \, moles$ of an ideal diatomic gas at temperature $T$. Heat $Q$ is supplied to this gas,due to which $2 \, moles$ of the gas are dissociated into atoms,but the temperature of the gas remains constant. Then:

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