An open organ pipe of length L vibrates in th | vedclass

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(B) For an open organ pipe,the length $L$ is given by $L = \frac{n \lambda}{2}$,where $\lambda$ is the wavelength and $n$ is an integer $(n = 1, 2, 3,

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at a distance $L/4$ from either end inside the tube

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(B) For an open organ pipe,the length $L$ is given by $L = \frac{n \lambda}{2}$,where $\lambda$ is the wavelength and $n$ is an integer $(n = 1, 2, 3, \dots)$.For the second harmonic mode,$n = 2$. Therefore,$L = \frac{2 \lambda}{2} = \lambda$.In an open organ pipe,the ends are always antinodes $(A)$ for displacement,which correspond to nodes for pressure variation. The nodes $(N)$ for displacement are where the pressure variation is maximum.In the second harmonic mode,the standing wave pattern consists of three antinodes and two nodes. The nodes are located at distances of $\frac{\lambda}{4}$ and $\frac{3\lambda}{4}$ from one end. Since $L = \lambda$,these positions are $\frac{L}{4}$ and $\frac{3L}{4}$ from one end.Thus,the pressure vibration is maximum at distances of $\frac{L}{4}$ from either end inside the tube.

An open organ pipe of length $L$ vibrates in the second harmonic mode. The pressure vibration is maximum

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