A glass tube 1.5 m long and open at both end | vedclass

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(B) The tube acts as a closed organ pipe because one end is closed by the water surface and the other is open. The resonance condition for a closed pi

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$6$

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(B) The tube acts as a closed organ pipe because one end is closed by the water surface and the other is open. The resonance condition for a closed pipe is given by $l = \frac{(2N - 1)v}{4f}$,where $N$ is the order of the resonance,$v = 330 \ m/s$ is the speed of sound,and $f = 660 \ Hz$ is the frequency.Substituting the values: $1.5 = \frac{(2N - 1) 	imes 330}{4 	imes 660}$.Simplifying the equation: $1.5 = \frac{(2N - 1)}{8}$.$12 = 2N - 1$.$2N = 13$.$N = 6.5$.Since $N$ must be an integer,the possible values for $N$ are $1, 2, 3, 4, 5, 6$. Thus,there are $6$ resonances.

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