An object starts a linear motion with velocity $'u^{\prime}$ and with uniform acceleration ' $a^{\prime}$, it acquires a velocity $'v^{\prime}$ in timet
$(a)$ Draw its velocity$-$time graph.
$(b)$ Obtain Ist equation of motion, $v=u+a t,$ for velocity $-$ time relation by using velocity$-$time graph.
$(c)$ A body moving with a velocity of $2\, m s ^{-1}$ acquires a velocity of $10 \,m s ^{-1}$ in $5\, s$. Find its acceleration.
$(a)$ The $v-t$ graph is as shown
$(b)$ Now, slope of the $v-t$ graph gives the acceleration of the motion.
$a=\frac{v-u}{t-0}=\frac{v-u}{t}$
Hence, $v=u+a t$
$(c)$ By using velocity - time graph
$u=2 m s ^{-1}, v=10 m s ^{-1}, t=5 s$
Using the expression $v=u+a t,$ we have
$a=\frac{10-2}{5-0}=\frac{8}{5}=1.6 m s ^{-2}$
Draw velocity-time graphs for the following situations
$(i)$ When body is moving with uniform velocity.
$(ii)$ When body is moving with variable velocity, but uniform acceleration.
$(iii)$ When body is moving with variable velocity, but uniform retardation.
$(iv)$ When body is moving with a variable velocity and variable acceleration.
Write true or false for the following statements
A quantitv which can be represented completely by magnitude alone is called a vector quantity.
Velocity$-$time graph for the motion of an object in a straight path is a straight line parallel to the time axis.
$(a)$ Identify the nature of motion of the body.
$(b)$ Find the acceleration of the body.
$(c)$ Draw the shape of distance-time graph for this type of motion.
What is the difference between uniform motion in a straight line and circular motion ?
Give an example of a body which covers a certain distance, but its displacement is zero