Draw velocity-time graphs for the following situations:
$(i)$ When a body is moving with uniform velocity.
$(ii)$ When a body is moving with variable velocity,but uniform acceleration.
$(iii)$ When a body is moving with variable velocity,but uniform retardation.
$(iv)$ When a body is moving with variable velocity and variable acceleration.
$(i)$ When a body is moving with uniform velocity.
$(ii)$ When a body is moving with variable velocity,but uniform acceleration.
$(iii)$ When a body is moving with variable velocity,but uniform retardation.
$(iv)$ When a body is moving with variable velocity and variable acceleration.
(N/A) The velocity-time graphs for the given situations are as follows:
$(i)$ For uniform velocity: The graph is a straight line parallel to the time axis,indicating that velocity does not change with time.
$(ii)$ For variable velocity with uniform acceleration: The graph is a straight line inclined to the time axis with a positive slope,indicating a constant rate of increase in velocity.
$(iii)$ For variable velocity with uniform retardation: The graph is a straight line inclined to the time axis with a negative slope,indicating a constant rate of decrease in velocity.
$(iv)$ For variable velocity and variable acceleration: The graph is a curve,indicating that the rate of change of velocity (acceleration) is not constant.
$(i)$ For uniform velocity: The graph is a straight line parallel to the time axis,indicating that velocity does not change with time.
$(ii)$ For variable velocity with uniform acceleration: The graph is a straight line inclined to the time axis with a positive slope,indicating a constant rate of increase in velocity.
$(iii)$ For variable velocity with uniform retardation: The graph is a straight line inclined to the time axis with a negative slope,indicating a constant rate of decrease in velocity.
$(iv)$ For variable velocity and variable acceleration: The graph is a curve,indicating that the rate of change of velocity (acceleration) is not constant.
Explore More
Similar Questions
The following table shows the position of three persons between $8.00\, am$ to $8.20\, am$.
Time Position of Person $A$ $(km)$ Position of Person $B$ $(km)$ Position of Person $C$ $(km)$ $8.00\, am$ $0$ $0$ $0$ $8.05\, am$ $4$ $5$ $10$ $8.10\, am$ $13$ $10$ $19$ $8.15\, am$ $20$ $15$ $24$ $8.20\, am$ $25$ $20$ $27$
$(i)$ Who is moving with constant speed?
$(ii)$ Who has travelled the maximum distance between $8.00\, am$ to $8.05\, am$?
$(iii)$ Calculate the average speed of person $A$ in $km\, h^{-1}$.
| Time | Position of Person $A$ $(km)$ | Position of Person $B$ $(km)$ | Position of Person $C$ $(km)$ |
| $8.00\, am$ | $0$ | $0$ | $0$ |
| $8.05\, am$ | $4$ | $5$ | $10$ |
| $8.10\, am$ | $13$ | $10$ | $19$ |
| $8.15\, am$ | $20$ | $15$ | $24$ |
| $8.20\, am$ | $25$ | $20$ | $27$ |
$(i)$ Who is moving with constant speed?
$(ii)$ Who has travelled the maximum distance between $8.00\, am$ to $8.05\, am$?
$(iii)$ Calculate the average speed of person $A$ in $km\, h^{-1}$.
Medium
View SolutionThe following displacement-time graph shows the positions of a body at different times. Calculate the velocity of the body as it moves from: $(i) A-B, (ii) B-C, (iii) C-D$.
Medium
View SolutionThe driver of a train $A$ travelling at a speed of $54\, km\, h^{-1}$ applies brakes and retards the train uniformly. The train stops in $5\, s$. Another train $B$ is travelling on the parallel track with a speed of $36\, km\, h^{-1}$. This driver also applies the brakes and the train retards uniformly. The train $B$ stops in $10\, s$. Plot the speed-time graph for both the trains on the same paper. Also,calculate the distance travelled by each train after the brakes were applied.
Medium
View SolutionThe displacement of a moving object in a given interval of time is zero. Would the distance travelled by the object also be zero? Justify your answer.
Easy
View Solution$(a)$ Derive the second equation of motion $S = ut + \frac{1}{2}at^2$ graphically,where the symbols have their usual meanings.
$(b)$ $A$ car accelerates uniformly from $18 \text{ km h}^{-1}$ to $36 \text{ km h}^{-1}$ in $5 \text{ s}$. Calculate the acceleration and the distance covered by the car in that time.
$(b)$ $A$ car accelerates uniformly from $18 \text{ km h}^{-1}$ to $36 \text{ km h}^{-1}$ in $5 \text{ s}$. Calculate the acceleration and the distance covered by the car in that time.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo