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(C) The object undergoes non-uniform circular motion,so it has both centripetal acceleration $(a_c)$ and tangential acceleration $(a_t)$.Given: veloci

Vedclass · Accepted Answer

$2.8$

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(C) The object undergoes non-uniform circular motion,so it has both centripetal acceleration $(a_c)$ and tangential acceleration $(a_t)$.Given: velocity $v = 30\, m/s$,radius $r = 450\, m$,and tangential acceleration $a_t = 2\, m/s^2$.The centripetal acceleration is $a_c = \frac{v^2}{r} = \frac{30^2}{450} = \frac{900}{450} = 2\, m/s^2$.The net acceleration $a$ is given by $a = \sqrt{a_c^2 + a_t^2}$.Substituting the values: $a = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} \approx 2.828\, m/s^2$.Thus,the acceleration is nearly $2.8\, m/s^2$.

An object is moving on a circular track of radius $450\, m$. At some instant,the object is moving at $30\, m/s$ and gaining speed at a uniform rate of $2\, m/s^2$. Its acceleration at this instant is nearly .......... $m/s^2$.

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