$A$ train is moving at a speed of $50\, m s^{-1}$ on a curved track of radius $250\, m$. What is its acceleration (in $, m s^{-2}$)?

The tangential acceleration of a particle moving in a circle of radius $1 \ m$ varies with time $t$ as shown in the graph (initial velocity of the particle is zero). The time after which the total acceleration of the particle makes an angle of $30^{\circ}$ with the radial acceleration is:

$A$ particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\vec a = (4\hat i + 3\hat j)\ m/s^2$ and $\vec p = (8\hat i - 6\hat j)\ kg \cdot m/s$. The motion of the particle is

$A$ body of mass $2 \,kg$ moves in a horizontal circular path of radius $5 \,m$. At an instant, its speed is $2 \sqrt{5} \,m/s$ and is increasing at the rate of $3 \,m/s^2$. The magnitude of the net force acting on the body at that instant is: (in $\,N$)

$A$ body is moving along a circular track of radius $100 \ m$ with velocity $20 \ m/s$. Its tangential acceleration is $3 \ m/s^{2}$,then its resultant acceleration will be (in $m/s^{2}$)

The distance of a particle moving on a circle of radius $12 \, m$ measured from a fixed point on the circle and measured along the circle is given by $s = 2t^3$ (in meters). The ratio of its tangential to centripetal acceleration at $t = 2 \, s$ is .........