An inverted tube barometer is kept on a lift moving downward with a deceleration $\alpha$. The density of mercury is $\rho$ and the acceleration due to gravity is $g$. If the atmospheric pressure is $P_0$,then:

  • A
    Height of the mercury column in the lift will be $\frac{P_0}{\rho(g + \alpha)}$
  • B
    Height of the mercury column in the lift will be $\frac{P_0}{\rho(g - \alpha)}$
  • C
    Height of the mercury column in the lift will be $\frac{P_0}{\rho g}$
  • D
    Height of the mercury column in the lift will be $\frac{P_0}{\rho \alpha}$

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$(a)$ Pressure decreases as one ascends the atmosphere. If the density of air is $\rho$,what is the change in pressure $dp$ over differential height $dh$?
$(b)$ Considering the pressure $P$ to be proportional to the density,find the pressure $P$ at a height $h$ if the pressure on the surface of the earth is $P_{0}$.
$(c)$ If $P_{0} = 1.03 \times 10^5 \text{ N/m}^2$,$\rho_0 = 1.29 \text{ kg/m}^3$,and $g = 9.8 \text{ m/s}^2$,at what height will the pressure drop to $\frac{1}{10}$ of the value at the surface of the earth?
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