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(C) According to the law of conservation of linear momentum,the total initial momentum of the system is zero because the device is initially stationar

Vedclass · Accepted Answer

Negative $x$ direction

Vedclass · Answer

(C) According to the law of conservation of linear momentum,the total initial momentum of the system is zero because the device is initially stationary.Since the total momentum must remain zero after the explosion,the sum of the momenta of the two pieces must be zero: $\vec{p}_1 + \vec{p}_2 = 0$.This implies $\vec{p}_2 = -\vec{p}_1$.If the first piece moves in the positive $x$ direction,its momentum vector is $\vec{p}_1 = p_1 \hat{i}$.Therefore,the momentum of the second piece must be $\vec{p}_2 = -p_1 \hat{i}$,which indicates that the second piece moves in the negative $x$ direction.Thus,option $C$ is correct.

An initially stationary device lying on a frictionless floor explodes into two pieces and slides across the floor. If one piece is moving in the positive $x$ direction,then the other piece is moving in:

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