(A) In an $LR$ series circuit,the voltage across the inductor $(V_L)$ and the voltage across the resistor $(V_R)$ are out of phase by $90^{\circ}$.The

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(A) In an $LR$ series circuit,the voltage across the inductor $(V_L)$ and the voltage across the resistor $(V_R)$ are out of phase by $90^{\circ}$.The total voltage $(V)$ of the ac supply is given by the phasor sum of the individual voltages:$V = \sqrt{V_L^2 + V_R^2}$Given:$V_L = 180 \ V$$V_R = 240 \ V$Substituting the values:$V = \sqrt{(180)^2 + (240)^2}$$V = \sqrt{32400 + 57600}$$V = \sqrt{90000}$$V = 300 \ V$Therefore,the voltage of the ac supply is $300 \ V$.

Class 12 Physics Alternating Current RL, RC and LC AC Circuits

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An inductor and a resistor are connected in series to an ac supply. If the potential differences across the inductor and the resistor are $180 \ V$ and $240 \ V$ respectively,then the voltage of the ac supply is (in $V$)

TS EAMCET 2025 All TS EAMCET

A
$300$
B
$420$
C
$60$
D
$210$

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Alternating Current

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RL, RC and LC AC Circuits

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An inductor and a resistor are connected in series to an ac supply. If the potential differences across the inductor and the resistor are $180 \ V$ and $240 \ V$ respectively,then the voltage of the ac supply is (in $V$)

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$A$ capacitor of reactance $4 \sqrt{3} \Omega$ and a resistor of resistance $4 \Omega$ are connected in series with an $AC$ source of peak value $8 \sqrt{2} \text{ V}$. The power dissipation in the circuit is . . . . . $\text{W}$.

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