The increase in pressure required to decrease | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formula for Bulk modulus $(B)$ is given by: $B = \frac{\Delta P}{-\Delta V / V}$.Rearranging for the change in pressure: $\Delta P = B 	imes

Vedclass · Accepted Answer

$84$

Vedclass · Answer

(D) The formula for Bulk modulus $(B)$ is given by: $B = \frac{\Delta P}{-\Delta V / V}$.Rearranging for the change in pressure: $\Delta P = B 	imes \left( -\frac{\Delta V}{V} ight)$.Given that the volume decreases by $0.004\%$,the volumetric strain is $\left| \frac{\Delta V}{V} ight| = \frac{0.004}{100} = 4 	imes 10^{-5}$.The Bulk modulus $B = 2100\,MPa = 2100 	imes 10^6\,Pa = 2.1 	imes 10^9\,Pa$.Substituting the values: $\Delta P = (2.1 	imes 10^9\,Pa) 	imes (4 	imes 10^{-5})$.$\Delta P = 8.4 	imes 10^4\,Pa = 84 	imes 10^3\,Pa = 84\,kPa$.

The increase in pressure required to decrease the $200\,L$ volume of a liquid by $0.004\%$ in a container is ............ $kPa$. (Bulk modulus of the liquid $= 2100\,MPa$)

Similar Questions

How much should the pressure on a litre of water be changed to compress it by $0.10\%?$

When compared with solids and liquids,the gases have

If the pressure on a body is increased from $200 \text{ kPa}$ to $250 \text{ kPa}$,the volume of the body decreases by $0.25 \%$. The compressibility of the material of the body is (in $m^2 \text{ N}^{-1}$)

Why is water more elastic than air?

Compute the fractional change in volume of a glass slab,when subjected to a hydraulic pressure of $10 \; atm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module